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ArmaGeddON..! (AGON) [-ArmaGeddON-]
7 years ago

1

hi,
It is written, “Take this value, and subtract it from the total number of visible ASCII characters”
Total number of ascii chars = 255
Visible = 255 -32 = 233 right? (If everything is right…where am I wrong??!!!)

Now, All non-visible characters just appear as they are e.g. space will just be blank 61, ,72,71
How can be this possible? even non-visible ascii characters have char code. (or it is done purposely?)

Nerd? Yup![/Spoiler]
<!- Hacker? Maybe!

[Spoiler]Hotel? Trivago! -!>

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ArmaGeddON..! (AGON) [-ArmaGeddON-]
7 years ago | edited 7 years ago

1

AND, c: Get the character at this position

at this position in our new ascii table?
or our string?

Nerd? Yup![/Spoiler]
<!- Hacker? Maybe!

[Spoiler]Hotel? Trivago! -!>

f0rk [HackingGuy]
7 years ago

1

You’ve got the right idea, just take a peek at the ascii table. :)

There’s no place like 127.0.0.1

darkcyber
7 years ago

1

I try to encrypt “a” and the answer is 62, am I right?

ArmaGeddON..! (AGON) [-ArmaGeddON-]
7 years ago

1

darkcyber, you are pretty close “a” is 61, not 62.

Nerd? Yup![/Spoiler]
<!- Hacker? Maybe!

[Spoiler]Hotel? Trivago! -!>

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